2(n-4)+4(1+4n)=-40

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Solution for 2(n-4)+4(1+4n)=-40 equation: 



2(n-4)+4(1+4n)=-40

We move all terms to the left:

2(n-4)+4(1+4n)-(-40)=0

We add all the numbers together, and all the variables

2(n-4)+4(4n+1)-(-40)=0

We add all the numbers together, and all the variables

2(n-4)+4(4n+1)+40=0

We multiply parentheses

2n+16n-8+4+40=0

We add all the numbers together, and all the variables

18n+36=0

We move all terms containing n to the left, all other terms to the right

18n=-36

n=-36/18

n=-2

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