2(n-4)=3-n/2

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Solution for 2(n-4)=3-n/2 equation: 


n in (-oo:+oo)

2*(n-4) = 3-(n/2) // - 3-(n/2)

2*(n-4)+n/2-3 = 0

(2^2*(n-4))/2+n/2+(-3*2)/2 = 0

2^2*(n-4)+n-3*2 = 0

5*n-16-6 = 0

5*n-22 = 0

(5*n-22)/2 = 0

(5*n-22)/2 = 0 // * 2

5*n-22 = 0

5*n-22 = 0 // + 22

5*n = 22 // : 5

n = 22/5

n = 22/5

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