2(n-4)=4(n-2)

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Solution for 2(n-4)=4(n-2) equation: 



2(n-4)=4(n-2)

We move all terms to the left:

2(n-4)-(4(n-2))=0

We multiply parentheses

2n-(4(n-2))-8=0



We calculate terms in parentheses: -(4(n-2)), so:

4(n-2)

We multiply parentheses

4n-8

Back to the equation:

-(4n-8)



We get rid of parentheses

2n-4n+8-8=0

We add all the numbers together, and all the variables

-2n=0

n=0/-2

n=0

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