2(n-4)=4n-18

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Solution for 2(n-4)=4n-18 equation: 



2(n-4)=4n-18

We move all terms to the left:

2(n-4)-(4n-18)=0

We multiply parentheses

2n-(4n-18)-8=0

We get rid of parentheses

2n-4n+18-8=0

We add all the numbers together, and all the variables

-2n+10=0

We move all terms containing n to the left, all other terms to the right

-2n=-10

n=-10/-2

n=+5

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