2(n-4)=6(n-2)

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Solution for 2(n-4)=6(n-2) equation: 



2(n-4)=6(n-2)

We move all terms to the left:

2(n-4)-(6(n-2))=0

We multiply parentheses

2n-(6(n-2))-8=0



We calculate terms in parentheses: -(6(n-2)), so:

6(n-2)

We multiply parentheses

6n-12

Back to the equation:

-(6n-12)



We get rid of parentheses

2n-6n+12-8=0

We add all the numbers together, and all the variables

-4n+4=0

We move all terms containing n to the left, all other terms to the right

-4n=-4

n=-4/-4

n=1

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