2(n-5)=-3(2n-10)

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Solution for 2(n-5)=-3(2n-10) equation: 



2(n-5)=-3(2n-10)

We move all terms to the left:

2(n-5)-(-3(2n-10))=0

We multiply parentheses

2n-(-3(2n-10))-10=0



We calculate terms in parentheses: -(-3(2n-10)), so:

-3(2n-10)

We multiply parentheses

-6n+30

Back to the equation:

-(-6n+30)



We get rid of parentheses

2n+6n-30-10=0

We add all the numbers together, and all the variables

8n-40=0

We move all terms containing n to the left, all other terms to the right

8n=40

n=40/8

n=5

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