2(n-5)=2(5+2n)-7n

Solution for 2(n-5)=2(5+2n)-7n equation:

2(n-5)=2(5+2n)-7n

We move all terms to the left:

2(n-5)-(2(5+2n)-7n)=0

We add all the numbers together, and all the variables

2(n-5)-(2(2n+5)-7n)=0

We multiply parentheses

2n-(2(2n+5)-7n)-10=0


We calculate terms in parentheses: -(2(2n+5)-7n), so:

2(2n+5)-7n

We add all the numbers together, and all the variables

-7n+2(2n+5)

We multiply parentheses

-7n+4n+10

We add all the numbers together, and all the variables

-3n+10

Back to the equation:

-(-3n+10)


We get rid of parentheses

2n+3n-10-10=0

We add all the numbers together, and all the variables

5n-20=0

We move all terms containing n to the left, all other terms to the right

5n=20

n=20/5

n=4