2(n-5)=3(n+3)

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Solution for 2(n-5)=3(n+3) equation: 



2(n-5)=3(n+3)

We move all terms to the left:

2(n-5)-(3(n+3))=0

We multiply parentheses

2n-(3(n+3))-10=0



We calculate terms in parentheses: -(3(n+3)), so:

3(n+3)

We multiply parentheses

3n+9

Back to the equation:

-(3n+9)



We get rid of parentheses

2n-3n-9-10=0

We add all the numbers together, and all the variables

-1n-19=0

We move all terms containing n to the left, all other terms to the right

-n=19

n=19/-1

n=-19

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