2(n-5)=3-(4+n)

Solution for 2(n-5)=3-(4+n) equation:

2(n-5)=3-(4+n)

We move all terms to the left:

2(n-5)-(3-(4+n))=0

We add all the numbers together, and all the variables

2(n-5)-(3-(n+4))=0

We multiply parentheses

2n-(3-(n+4))-10=0


We calculate terms in parentheses: -(3-(n+4)), so:

3-(n+4)

determiningTheFunctionDomain
-(n+4)+3

We get rid of parentheses

-n-4+3

We add all the numbers together, and all the variables

-1n-1

Back to the equation:

-(-1n-1)


We get rid of parentheses

2n+1n+1-10=0

We add all the numbers together, and all the variables

3n-9=0

We move all terms containing n to the left, all other terms to the right

3n=9

n=9/3

n=3