2(n-5)=4(n+1)

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Solution for 2(n-5)=4(n+1) equation:


Simplifying
2(n + -5) = 4(n + 1)

Reorder the terms:
2(-5 + n) = 4(n + 1)
(-5 * 2 + n * 2) = 4(n + 1)
(-10 + 2n) = 4(n + 1)

Reorder the terms:
-10 + 2n = 4(1 + n)
-10 + 2n = (1 * 4 + n * 4)
-10 + 2n = (4 + 4n)

Solving
-10 + 2n = 4 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
-10 + 2n + -4n = 4 + 4n + -4n

Combine like terms: 2n + -4n = -2n
-10 + -2n = 4 + 4n + -4n

Combine like terms: 4n + -4n = 0
-10 + -2n = 4 + 0
-10 + -2n = 4

Add '10' to each side of the equation.
-10 + 10 + -2n = 4 + 10

Combine like terms: -10 + 10 = 0
0 + -2n = 4 + 10
-2n = 4 + 10

Combine like terms: 4 + 10 = 14
-2n = 14

Divide each side by '-2'.
n = -7

Simplifying
n = -7

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