2(n-5)=4-2(7-n)

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Solution for 2(n-5)=4-2(7-n) equation:


Simplifying
2(n + -5) = 4 + -2(7 + -1n)

Reorder the terms:
2(-5 + n) = 4 + -2(7 + -1n)
(-5 * 2 + n * 2) = 4 + -2(7 + -1n)
(-10 + 2n) = 4 + -2(7 + -1n)
-10 + 2n = 4 + (7 * -2 + -1n * -2)
-10 + 2n = 4 + (-14 + 2n)

Combine like terms: 4 + -14 = -10
-10 + 2n = -10 + 2n

Add '10' to each side of the equation.
-10 + 10 + 2n = -10 + 10 + 2n

Combine like terms: -10 + 10 = 0
0 + 2n = -10 + 10 + 2n
2n = -10 + 10 + 2n

Combine like terms: -10 + 10 = 0
2n = 0 + 2n
2n = 2n

Add '-2n' to each side of the equation.
2n + -2n = 2n + -2n

Combine like terms: 2n + -2n = 0
0 = 2n + -2n

Combine like terms: 2n + -2n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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