2(n-7)=3(n+4)

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Solution for 2(n-7)=3(n+4) equation: 



2(n-7)=3(n+4)

We move all terms to the left:

2(n-7)-(3(n+4))=0

We multiply parentheses

2n-(3(n+4))-14=0



We calculate terms in parentheses: -(3(n+4)), so:

3(n+4)

We multiply parentheses

3n+12

Back to the equation:

-(3n+12)



We get rid of parentheses

2n-3n-12-14=0

We add all the numbers together, and all the variables

-1n-26=0

We move all terms containing n to the left, all other terms to the right

-n=26

n=26/-1

n=-26

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