2(n/6)=3(n+9)

Solution for 2(n/6)=3(n+9) equation:

2(n/6)=3(n+9)

We move all terms to the left:

2(n/6)-(3(n+9))=0

We add all the numbers together, and all the variables

2(+n/6)-(3(n+9))=0

We multiply parentheses

2n-(3(n+9))=0


We calculate terms in parentheses: -(3(n+9)), so:

3(n+9)

We multiply parentheses

3n+27

Back to the equation:

-(3n+27)


We get rid of parentheses

2n-3n-27=0

We add all the numbers together, and all the variables

-1n-27=0

We move all terms containing n to the left, all other terms to the right

-n=27

n=27/-1

n=-27