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n in (-oo:+oo)
2*((n^1)/3) = (3/2)*n+(1/2)*n-(1/3)+1 // - (3/2)*n+(1/2)*n-(1/3)+1
2*((n^1)/3)-((3/2)*n)-((1/2)*n)+1/3-1 = 0
2*(n/3)+(-3/2)*n+(-1/2)*n+1/3-1 = 0
-4/3*n-2/3 = 0 // + 2/3
-4/3*n = 2/3 // : -4/3
n = 2/3/(-4/3)
n = -1/2
n = -1/2
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