2(p+1)+7(3p+2)=7(p-4)

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Solution for 2(p+1)+7(3p+2)=7(p-4) equation: 



2(p+1)+7(3p+2)=7(p-4)

We move all terms to the left:

2(p+1)+7(3p+2)-(7(p-4))=0

We multiply parentheses

2p+21p-(7(p-4))+2+14=0



We calculate terms in parentheses: -(7(p-4)), so:

7(p-4)

We multiply parentheses

7p-28

Back to the equation:

-(7p-28)



We add all the numbers together, and all the variables

23p-(7p-28)+16=0

We get rid of parentheses

23p-7p+28+16=0

We add all the numbers together, and all the variables

16p+44=0

We move all terms containing p to the left, all other terms to the right

16p=-44

p=-44/16

p=-2+3/4

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