2(p+3)=-2(p-4)+22

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Solution for 2(p+3)=-2(p-4)+22 equation: 



2(p+3)=-2(p-4)+22

We move all terms to the left:

2(p+3)-(-2(p-4)+22)=0

We multiply parentheses

2p-(-2(p-4)+22)+6=0



We calculate terms in parentheses: -(-2(p-4)+22), so:

-2(p-4)+22

We multiply parentheses

-2p+8+22

We add all the numbers together, and all the variables

-2p+30

Back to the equation:

-(-2p+30)



We get rid of parentheses

2p+2p-30+6=0

We add all the numbers together, and all the variables

4p-24=0

We move all terms containing p to the left, all other terms to the right

4p=24

p=24/4

p=6

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