2(p+4)=6(p-1)-4(p-1)

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Solution for 2(p+4)=6(p-1)-4(p-1) equation: 



2(p+4)=6(p-1)-4(p-1)

We move all terms to the left:

2(p+4)-(6(p-1)-4(p-1))=0

We multiply parentheses

2p-(6(p-1)-4(p-1))+8=0



We calculate terms in parentheses: -(6(p-1)-4(p-1)), so:

6(p-1)-4(p-1)

We multiply parentheses

6p-4p-6+4

We add all the numbers together, and all the variables

2p-2

Back to the equation:

-(2p-2)



We get rid of parentheses

2p-2p+2+8=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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