2(p+q)(p-q)=

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Solution for 2(p+q)(p-q)= equation:


Simplifying
2(p + q)(p + -1q) = 0

Multiply (p + q) * (p + -1q)
2(p(p + -1q) + q(p + -1q)) = 0
2((p * p + -1q * p) + q(p + -1q)) = 0

Reorder the terms:
2((-1pq + p2) + q(p + -1q)) = 0
2((-1pq + p2) + q(p + -1q)) = 0
2(-1pq + p2 + (p * q + -1q * q)) = 0
2(-1pq + p2 + (pq + -1q2)) = 0

Reorder the terms:
2(-1pq + pq + p2 + -1q2) = 0

Combine like terms: -1pq + pq = 0
2(0 + p2 + -1q2) = 0
2(p2 + -1q2) = 0
(p2 * 2 + -1q2 * 2) = 0
(2p2 + -2q2) = 0

Solving
2p2 + -2q2 = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '2q2' to each side of the equation.
2p2 + -2q2 + 2q2 = 0 + 2q2

Combine like terms: -2q2 + 2q2 = 0
2p2 + 0 = 0 + 2q2
2p2 = 0 + 2q2
Remove the zero:
2p2 = 2q2

Divide each side by '2'.
p2 = q2

Simplifying
p2 = q2

Take the square root of each side:
p = {-1q, q}

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