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2(p-(3p+20)+14)=2(p+6)
We move all terms to the left:
2(p-(3p+20)+14)-(2(p+6))=0
We calculate terms in parentheses: -(2(p+6)), so:We get rid of parentheses
2(p+6)
We multiply parentheses
2p+12
Back to the equation:
-(2p+12)
2(p-(3p+20)+14)-2p-12=0
We add all the numbers together, and all the variables
-2p+2(p-(3p+20)+14)-12=0
We move all terms containing p to the left, all other terms to the right
-2p+2(p-(3p+20)+14)=12
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