2(p-1)+7(3p+2)=7(p-4

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Solution for 2(p-1)+7(3p+2)=7(p-4 equation: 



2(p-1)+7(3p+2)=7(p-4

We move all terms to the left:

2(p-1)+7(3p+2)-(7(p-4)=0

We multiply parentheses

2p+21p-(7(p-4)-2+14=0

We add all the numbers together, and all the variables

23p-(7(p-4)-2+14=0

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