2(p-1)+7(3p-2)=7(p-4)

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Solution for 2(p-1)+7(3p-2)=7(p-4) equation: 



2(p-1)+7(3p-2)=7(p-4)

We move all terms to the left:

2(p-1)+7(3p-2)-(7(p-4))=0

We multiply parentheses

2p+21p-(7(p-4))-2-14=0



We calculate terms in parentheses: -(7(p-4)), so:

7(p-4)

We multiply parentheses

7p-28

Back to the equation:

-(7p-28)



We add all the numbers together, and all the variables

23p-(7p-28)-16=0

We get rid of parentheses

23p-7p+28-16=0

We add all the numbers together, and all the variables

16p+12=0

We move all terms containing p to the left, all other terms to the right

16p=-12

p=-12/16

p=-3/4

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