2(p-3)+3(p+2)+4(p-1)=5(p+4)

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Solution for 2(p-3)+3(p+2)+4(p-1)=5(p+4) equation: 



2(p-3)+3(p+2)+4(p-1)=5(p+4)

We move all terms to the left:

2(p-3)+3(p+2)+4(p-1)-(5(p+4))=0

We multiply parentheses

2p+3p+4p-(5(p+4))-6+6-4=0



We calculate terms in parentheses: -(5(p+4)), so:

5(p+4)

We multiply parentheses

5p+20

Back to the equation:

-(5p+20)



We add all the numbers together, and all the variables

9p-(5p+20)-4=0

We get rid of parentheses

9p-5p-20-4=0

We add all the numbers together, and all the variables

4p-24=0

We move all terms containing p to the left, all other terms to the right

4p=24

p=24/4

p=6

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