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2(q+1)=-3(2q-1)+4(2q+1)
We move all terms to the left:
2(q+1)-(-3(2q-1)+4(2q+1))=0
We multiply parentheses
2q-(-3(2q-1)+4(2q+1))+2=0
We calculate terms in parentheses: -(-3(2q-1)+4(2q+1)), so:We get rid of parentheses
-3(2q-1)+4(2q+1)
We multiply parentheses
-6q+8q+3+4
We add all the numbers together, and all the variables
2q+7
Back to the equation:
-(2q+7)
2q-2q-7+2=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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