2(q-3)=3(-q+4)

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Solution for 2(q-3)=3(-q+4) equation: 



2(q-3)=3(-q+4)

We move all terms to the left:

2(q-3)-(3(-q+4))=0

We add all the numbers together, and all the variables

2(q-3)-(3(-1q+4))=0

We multiply parentheses

2q-(3(-1q+4))-6=0



We calculate terms in parentheses: -(3(-1q+4)), so:

3(-1q+4)

We multiply parentheses

-3q+12

Back to the equation:

-(-3q+12)



We get rid of parentheses

2q+3q-12-6=0

We add all the numbers together, and all the variables

5q-18=0

We move all terms containing q to the left, all other terms to the right

5q=18

q=18/5

q=3+3/5

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