2(q-4)+6=3(q-5)64-6+

Solution for 2(q-4)+6=3(q-5)64-6+ equation:

2(q-4)+6=3(q-5)64-6+

We move all terms to the left:

2(q-4)+6-(3(q-5)64-6+)=0

We multiply parentheses

2q-(3(q-5)64-6+)-8+6=0


We calculate terms in parentheses: -(3(q-5)64-6+), so:

3(q-5)64-6+

We add all the numbers together, and all the variables

3(q-5)64

We multiply parentheses

192q-960

Back to the equation:

-(192q-960)


We add all the numbers together, and all the variables

2q-(192q-960)-2=0

We get rid of parentheses

2q-192q+960-2=0

We add all the numbers together, and all the variables

-190q+958=0

We move all terms containing q to the left, all other terms to the right

-190q=-958

q=-958/-190

q=5+4/95