2(r+3)-4r=18

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Solution for 2(r+3)-4r=18 equation: 



2(r+3)-4r=18

We move all terms to the left:

2(r+3)-4r-(18)=0

We add all the numbers together, and all the variables

-4r+2(r+3)-18=0

We multiply parentheses

-4r+2r+6-18=0

We add all the numbers together, and all the variables

-2r-12=0

We move all terms containing r to the left, all other terms to the right

-2r=12

r=12/-2

r=-6

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