2(r+3)-6(1-11r)=8r+r

Solution for 2(r+3)-6(1-11r)=8r+r equation:

Simplifying
2(r + 3) + -6(1 + -11r) = 8r + r

Reorder the terms:
2(3 + r) + -6(1 + -11r) = 8r + r
(3 * 2 + r * 2) + -6(1 + -11r) = 8r + r
(6 + 2r) + -6(1 + -11r) = 8r + r
6 + 2r + (1 * -6 + -11r * -6) = 8r + r
6 + 2r + (-6 + 66r) = 8r + r

Reorder the terms:
6 + -6 + 2r + 66r = 8r + r

Combine like terms: 6 + -6 = 0
0 + 2r + 66r = 8r + r
2r + 66r = 8r + r

Combine like terms: 2r + 66r = 68r
68r = 8r + r

Combine like terms: 8r + r = 9r
68r = 9r

Solving
68r = 9r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-9r' to each side of the equation.
68r + -9r = 9r + -9r

Combine like terms: 68r + -9r = 59r
59r = 9r + -9r

Combine like terms: 9r + -9r = 0
59r = 0

Divide each side by '59'.
r = 0

Simplifying
r = 0