2(r+4)+8=(r+3)4

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Solution for 2(r+4)+8=(r+3)4 equation: 


Simplifying
2(r + 4) + 8 = (r + 3) * 4

Reorder the terms:
2(4 + r) + 8 = (r + 3) * 4
(4 * 2 + r * 2) + 8 = (r + 3) * 4
(8 + 2r) + 8 = (r + 3) * 4

Reorder the terms:
8 + 8 + 2r = (r + 3) * 4

Combine like terms: 8 + 8 = 16
16 + 2r = (r + 3) * 4

Reorder the terms:
16 + 2r = (3 + r) * 4

Reorder the terms for easier multiplication:
16 + 2r = 4(3 + r)
16 + 2r = (3 * 4 + r * 4)
16 + 2r = (12 + 4r)

Solving
16 + 2r = 12 + 4r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-4r' to each side of the equation.
16 + 2r + -4r = 12 + 4r + -4r

Combine like terms: 2r + -4r = -2r
16 + -2r = 12 + 4r + -4r

Combine like terms: 4r + -4r = 0
16 + -2r = 12 + 0
16 + -2r = 12

Add '-16' to each side of the equation.
16 + -16 + -2r = 12 + -16

Combine like terms: 16 + -16 = 0
0 + -2r = 12 + -16
-2r = 12 + -16

Combine like terms: 12 + -16 = -4
-2r = -4

Divide each side by '-2'.
r = 2

Simplifying
r = 2

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