2(r+4)-3(r+1)=11

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Solution for 2(r+4)-3(r+1)=11 equation: 



2(r+4)-3(r+1)=11

We move all terms to the left:

2(r+4)-3(r+1)-(11)=0

We multiply parentheses

2r-3r+8-3-11=0

We add all the numbers together, and all the variables

-1r-6=0

We move all terms containing r to the left, all other terms to the right

-r=6

r=6/-1

r=-6

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