2(r+4)=(r+-7)

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Solution for 2(r+4)=(r+-7) equation: 



2(r+4)=(r+-7)

We move all terms to the left:

2(r+4)-((r+-7))=0

We add all the numbers together, and all the variables

2(r+4)-((r-7))=0

We multiply parentheses

2r-((r-7))+8=0



We calculate terms in parentheses: -((r-7)), so:

(r-7)

We get rid of parentheses

r-7

Back to the equation:

-(r-7)



We get rid of parentheses

2r-r+7+8=0

We add all the numbers together, and all the variables

r+15=0

We move all terms containing r to the left, all other terms to the right

r=-15

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