2(r+5)-(2+8r)=3(1-3r)

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Solution for 2(r+5)-(2+8r)=3(1-3r) equation: 



2(r+5)-(2+8r)=3(1-3r)

We move all terms to the left:

2(r+5)-(2+8r)-(3(1-3r))=0

We add all the numbers together, and all the variables

2(r+5)-(8r+2)-(3(-3r+1))=0

We multiply parentheses

2r-(8r+2)-(3(-3r+1))+10=0

We get rid of parentheses

2r-8r-(3(-3r+1))-2+10=0



We calculate terms in parentheses: -(3(-3r+1)), so:

3(-3r+1)

We multiply parentheses

-9r+3

Back to the equation:

-(-9r+3)



We add all the numbers together, and all the variables

-6r-(-9r+3)+8=0

We get rid of parentheses

-6r+9r-3+8=0

We add all the numbers together, and all the variables

3r+5=0

We move all terms containing r to the left, all other terms to the right

3r=-5

r=-5/3

r=-1+2/3

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