2(r+5)-2(2r-8)=42

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Solution for 2(r+5)-2(2r-8)=42 equation: 



2(r+5)-2(2r-8)=42

We move all terms to the left:

2(r+5)-2(2r-8)-(42)=0

We multiply parentheses

2r-4r+10+16-42=0

We add all the numbers together, and all the variables

-2r-16=0

We move all terms containing r to the left, all other terms to the right

-2r=16

r=16/-2

r=-8

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