2(r+5)-4(r-1)=31

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Solution for 2(r+5)-4(r-1)=31 equation: 



2(r+5)-4(r-1)=31

We move all terms to the left:

2(r+5)-4(r-1)-(31)=0

We multiply parentheses

2r-4r+10+4-31=0

We add all the numbers together, and all the variables

-2r-17=0

We move all terms containing r to the left, all other terms to the right

-2r=17

r=17/-2

r=-8+1/2

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