2(r+s)-(r+s)=

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Solution for 2(r+s)-(r+s)= equation:


Simplifying
2(r + s) + -1(r + s) = 0
(r * 2 + s * 2) + -1(r + s) = 0
(2r + 2s) + -1(r + s) = 0
2r + 2s + (r * -1 + s * -1) = 0
2r + 2s + (-1r + -1s) = 0

Reorder the terms:
2r + -1r + 2s + -1s = 0

Combine like terms: 2r + -1r = 1r
1r + 2s + -1s = 0

Combine like terms: 2s + -1s = 1s
1r + 1s = 0

Solving
1r + 1s = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-1s' to each side of the equation.
1r + 1s + -1s = 0 + -1s

Combine like terms: 1s + -1s = 0
1r + 0 = 0 + -1s
1r = 0 + -1s
Remove the zero:
1r = -1s

Divide each side by '1'.
r = -1s

Simplifying
r = -1s

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