2(r-3)+36=-4r

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Solution for 2(r-3)+36=-4r equation: 



2(r-3)+36=-4r

We move all terms to the left:

2(r-3)+36-(-4r)=0

We multiply parentheses

2r-(-4r)-6+36=0

We get rid of parentheses

2r+4r-6+36=0

We add all the numbers together, and all the variables

6r+30=0

We move all terms containing r to the left, all other terms to the right

6r=-30

r=-30/6

r=-5

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