2(r-3)+5r=8(r-1)

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Solution for 2(r-3)+5r=8(r-1) equation: 



2(r-3)+5r=8(r-1)

We move all terms to the left:

2(r-3)+5r-(8(r-1))=0

We add all the numbers together, and all the variables

5r+2(r-3)-(8(r-1))=0

We multiply parentheses

5r+2r-(8(r-1))-6=0



We calculate terms in parentheses: -(8(r-1)), so:

8(r-1)

We multiply parentheses

8r-8

Back to the equation:

-(8r-8)



We add all the numbers together, and all the variables

7r-(8r-8)-6=0

We get rid of parentheses

7r-8r+8-6=0

We add all the numbers together, and all the variables

-1r+2=0

We move all terms containing r to the left, all other terms to the right

-r=-2

r=-2/-1

r=+2

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