2(r-3)+6=16

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Solution for 2(r-3)+6=16 equation: 



2(r-3)+6=16

We move all terms to the left:

2(r-3)+6-(16)=0

We add all the numbers together, and all the variables

2(r-3)-10=0

We multiply parentheses

2r-6-10=0

We add all the numbers together, and all the variables

2r-16=0

We move all terms containing r to the left, all other terms to the right

2r=16

r=16/2

r=8

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