2(r-3)+6r=4(r-10)+2r+8

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Solution for 2(r-3)+6r=4(r-10)+2r+8 equation: 



2(r-3)+6r=4(r-10)+2r+8

We move all terms to the left:

2(r-3)+6r-(4(r-10)+2r+8)=0

We add all the numbers together, and all the variables

6r+2(r-3)-(4(r-10)+2r+8)=0

We multiply parentheses

6r+2r-(4(r-10)+2r+8)-6=0



We calculate terms in parentheses: -(4(r-10)+2r+8), so:

4(r-10)+2r+8

We add all the numbers together, and all the variables

2r+4(r-10)+8

We multiply parentheses

2r+4r-40+8

We add all the numbers together, and all the variables

6r-32

Back to the equation:

-(6r-32)



We add all the numbers together, and all the variables

8r-(6r-32)-6=0

We get rid of parentheses

8r-6r+32-6=0

We add all the numbers together, and all the variables

2r+26=0

We move all terms containing r to the left, all other terms to the right

2r=-26

r=-26/2

r=-13

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