2(r-3)-5(r+2)=

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Solution for 2(r-3)-5(r+2)= equation:


2(r-3)-5(r+2)=0

We simplify the equation to the form, which is simple to understand
2(r-3)-5(r+2)=0

Reorder the terms in parentheses
+(+2r-6)-5*(r+2)=0

Remove unnecessary parentheses
+2r-6-5+*(+r+2+)=0

Reorder the terms in parentheses
+2r-6+(-5r-10)=0

Remove unnecessary parentheses
+2r-6-5r-10=0

We move all terms containing r to the left and all other terms to the right.
+2r-5r=0+6+10

We simplify left and right side of the equation.
-3r=+16

We divide both sides of the equation by -3 to get r.
r=-5.3333333333333

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