2(s+1)=3(b-6)

Solution for 2(s+1)=3(b-6) equation:

Simplifying
2(s + 1) = 3(b + -6)

Reorder the terms:
2(1 + s) = 3(b + -6)
(1 * 2 + s * 2) = 3(b + -6)
(2 + 2s) = 3(b + -6)

Reorder the terms:
2 + 2s = 3(-6 + b)
2 + 2s = (-6 * 3 + b * 3)
2 + 2s = (-18 + 3b)

Solving
2 + 2s = -18 + 3b

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 2s = -18 + -2 + 3b

Combine like terms: 2 + -2 = 0
0 + 2s = -18 + -2 + 3b
2s = -18 + -2 + 3b

Combine like terms: -18 + -2 = -20
2s = -20 + 3b

Divide each side by '2'.
s = -10 + 1.5b

Simplifying
s = -10 + 1.5b