2(s+3(s-1))=18+5s

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Solution for 2(s+3(s-1))=18+5s equation: 



2(s+3(s-1))=18+5s

We move all terms to the left:

2(s+3(s-1))-(18+5s)=0

We add all the numbers together, and all the variables

2(s+3(s-1))-(5s+18)=0

We get rid of parentheses

2(s+3(s-1))-5s-18=0

We add all the numbers together, and all the variables

-5s+2(s+3(s-1))-18=0

We move all terms containing s to the left, all other terms to the right

-5s+2(s+3(s-1))=18

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