2(s+3)+1=17

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Solution for 2(s+3)+1=17 equation: 



2(s+3)+1=17

We move all terms to the left:

2(s+3)+1-(17)=0

We add all the numbers together, and all the variables

2(s+3)-16=0

We multiply parentheses

2s+6-16=0

We add all the numbers together, and all the variables

2s-10=0

We move all terms containing s to the left, all other terms to the right

2s=10

s=10/2

s=5

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