2(s+3)+1=17

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Solution for 2(s+3)+1=17 equation:



2(s+3)+1=17
We move all terms to the left:
2(s+3)+1-(17)=0
We add all the numbers together, and all the variables
2(s+3)-16=0
We multiply parentheses
2s+6-16=0
We add all the numbers together, and all the variables
2s-10=0
We move all terms containing s to the left, all other terms to the right
2s=10
s=10/2
s=5

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