2(s+3)+s=4s+5

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Solution for 2(s+3)+s=4s+5 equation: 



2(s+3)+s=4s+5

We move all terms to the left:

2(s+3)+s-(4s+5)=0

We add all the numbers together, and all the variables

s+2(s+3)-(4s+5)=0

We multiply parentheses

s+2s-(4s+5)+6=0

We get rid of parentheses

s+2s-4s-5+6=0

We add all the numbers together, and all the variables

-1s+1=0

We move all terms containing s to the left, all other terms to the right

-s=-1

s=-1/-1

s=1

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