2(s+3)=+4s+s+5

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Solution for 2(s+3)=+4s+s+5 equation:



2(s+3)=+4s+s+5
We move all terms to the left:
2(s+3)-(+4s+s+5)=0
We add all the numbers together, and all the variables
2(s+3)-(5s+5)=0
We multiply parentheses
2s-(5s+5)+6=0
We get rid of parentheses
2s-5s-5+6=0
We add all the numbers together, and all the variables
-3s+1=0
We move all terms containing s to the left, all other terms to the right
-3s=-1
s=-1/-3
s=1/3

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