2(s+3)=+s+4s+5

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Solution for 2(s+3)=+s+4s+5 equation: 



2(s+3)=+s+4s+5

We move all terms to the left:

2(s+3)-(+s+4s+5)=0

We add all the numbers together, and all the variables

2(s+3)-(5s+5)=0

We multiply parentheses

2s-(5s+5)+6=0

We get rid of parentheses

2s-5s-5+6=0

We add all the numbers together, and all the variables

-3s+1=0

We move all terms containing s to the left, all other terms to the right

-3s=-1

s=-1/-3

s=1/3

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