2(s+3)=4s+5

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Solution for 2(s+3)=4s+5 equation: 



2(s+3)=4s+5

We move all terms to the left:

2(s+3)-(4s+5)=0

We multiply parentheses

2s-(4s+5)+6=0

We get rid of parentheses

2s-4s-5+6=0

We add all the numbers together, and all the variables

-2s+1=0

We move all terms containing s to the left, all other terms to the right

-2s=-1

s=-1/-2

s=1/2

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