2(s+3)=4s+5

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Solution for 2(s+3)=4s+5 equation:



2(s+3)=4s+5
We move all terms to the left:
2(s+3)-(4s+5)=0
We multiply parentheses
2s-(4s+5)+6=0
We get rid of parentheses
2s-4s-5+6=0
We add all the numbers together, and all the variables
-2s+1=0
We move all terms containing s to the left, all other terms to the right
-2s=-1
s=-1/-2
s=1/2

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