2(s+4)+3(s+1)=4

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Solution for 2(s+4)+3(s+1)=4 equation:



2(s+4)+3(s+1)=4
We move all terms to the left:
2(s+4)+3(s+1)-(4)=0
We multiply parentheses
2s+3s+8+3-4=0
We add all the numbers together, and all the variables
5s+7=0
We move all terms containing s to the left, all other terms to the right
5s=-7
s=-7/5
s=-1+2/5

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