2(s+4)+3(s+1)=4

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Solution for 2(s+4)+3(s+1)=4 equation: 



2(s+4)+3(s+1)=4

We move all terms to the left:

2(s+4)+3(s+1)-(4)=0

We multiply parentheses

2s+3s+8+3-4=0

We add all the numbers together, and all the variables

5s+7=0

We move all terms containing s to the left, all other terms to the right

5s=-7

s=-7/5

s=-1+2/5

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