2(s+4)=3(s-4)

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Solution for 2(s+4)=3(s-4) equation: 



2(s+4)=3(s-4)

We move all terms to the left:

2(s+4)-(3(s-4))=0

We multiply parentheses

2s-(3(s-4))+8=0



We calculate terms in parentheses: -(3(s-4)), so:

3(s-4)

We multiply parentheses

3s-12

Back to the equation:

-(3s-12)



We get rid of parentheses

2s-3s+12+8=0

We add all the numbers together, and all the variables

-1s+20=0

We move all terms containing s to the left, all other terms to the right

-s=-20

s=-20/-1

s=+20

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