2(s+51)=(10s-13)+(4s+7)

Solution for 2(s+51)=(10s-13)+(4s+7) equation:

2(s+51)=(10s-13)+(4s+7)

We move all terms to the left:

2(s+51)-((10s-13)+(4s+7))=0

We multiply parentheses

2s-((10s-13)+(4s+7))+102=0


We calculate terms in parentheses: -((10s-13)+(4s+7)), so:

(10s-13)+(4s+7)

We get rid of parentheses

10s+4s-13+7

We add all the numbers together, and all the variables

14s-6

Back to the equation:

-(14s-6)


We get rid of parentheses

2s-14s+6+102=0

We add all the numbers together, and all the variables

-12s+108=0

We move all terms containing s to the left, all other terms to the right

-12s=-108

s=-108/-12

s=+9