2(s-1)+3(s-3)+s=1

Solution for 2(s-1)+3(s-3)+s=1 equation:

Simplifying
2(s + -1) + 3(s + -3) + s = 1

Reorder the terms:
2(-1 + s) + 3(s + -3) + s = 1
(-1 * 2 + s * 2) + 3(s + -3) + s = 1
(-2 + 2s) + 3(s + -3) + s = 1

Reorder the terms:
-2 + 2s + 3(-3 + s) + s = 1
-2 + 2s + (-3 * 3 + s * 3) + s = 1
-2 + 2s + (-9 + 3s) + s = 1

Reorder the terms:
-2 + -9 + 2s + 3s + s = 1

Combine like terms: -2 + -9 = -11
-11 + 2s + 3s + s = 1

Combine like terms: 2s + 3s = 5s
-11 + 5s + s = 1

Combine like terms: 5s + s = 6s
-11 + 6s = 1

Solving
-11 + 6s = 1

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 6s = 1 + 11

Combine like terms: -11 + 11 = 0
0 + 6s = 1 + 11
6s = 1 + 11

Combine like terms: 1 + 11 = 12
6s = 12

Divide each side by '6'.
s = 2

Simplifying
s = 2